Sorry if its already been answered.
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Sorry if its already been answered.
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We can approximate the sum of this infinite harmonic sequence with the natural log function (Think of it like integration instead of addition), and the error is less than $$$1$$$ (It's called the Euler-Mascheroni constant)
lets say it is smaller than
1 + 1/2 + 1/2 + 1/4 + 1/4 + 1/4 + 1/4 + 1/8 + ...
(we have1/2^i
2^i
times) and(1/2^i) * 2^i = 1
so we have n * log(n)Good job bruh
Bibek..rocks
We can apply integral test for it 1+/2+1/3+...+1/n < integral of (1/x)dx with lower limit 1 and upper limit n. So the sum is < log(n)
Natural log function