Hi everyone, I am solving a problem where i need to find the min number of coins such that total sum is equal to sum. My given solution is not working if i use long long ans = INT_MAX; and it is taking too long but it is working long long ans = 10000000; for the given testcase. Can somebody help me to find the issue why it is not working with INT_MAX? For example, if the coins are {1,5,7} and the desired sum is 11, an optimal solution is 5+5+1 which requires 3 coins. I would request you to copy paste in your ide and run with below testcase because ans= INT_MAX making code stuck in loop.

#include <bits/stdc++.h>
using namespace std;
#define ll long long int
#define f(i, p, q) for (int i = p; i < q; i++)

ll dp[1000003];

long long solve(int n, int sum, int *ar) {
    if (sum == 0) return 0;
    if (dp[sum] != INT_MAX) return dp[sum];

    // long long ans = 10000000;
     long long ans = INT_MAX;

    for (int i = 0; i < n; i++) {
        if (sum - ar[i] >= 0) {
            ans = min(ans, 1 + solve(n, sum - ar[i], ar));
        }
    }

    dp[sum] = ans;
    return ans;
}
int main()
{
    int n,m;
    cin >> n>>m;
    int ar[n];
    f(i,0,n)cin>>ar[i];
    f(i,0,1000003)dp[i]= INT_MAX;
    int a =solve(n,m, ar);
    cout<< ((a== 10000000)? -1 : a);
}

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