Блог пользователя ajijulquanta

Автор ajijulquanta, история, 4 дня назад, По-английски

Problem 2. Doma is blindfolded and there are 50 two-rupee coins on the table, ten of which are moons. Now these coins should be flipped as desired and divided into two forms in such a way that each cup has equal number of moons. (One side of the coin has the moon and the other the stars).

[Translated by google translate]

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4 дня назад, # |
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Divide the coins into two piles, one pile of ten coins and the other pile of forty coins, if the pile of ten coins has A moon, then the pile of ten coins has 10-A moon, and the pile of ten coins will flip over and both will have 10-A moon.

Please forgive the retarded translation software.

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4 дня назад, # |
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Divide the 50 pile into 2 different stacks one will have x moon y-x stars

other will have 50-y-x moons and x stars now flip the other stack we have equal number of moons

Looking forward for more puzzles.