Is this code below works on all platform with C++11 compiler?
I know that earlier we had to to use "%I64d" for Windows platform and "%lld" for linux like platforms.
long long = (long long)1e18;
printf("%lld\n", a);
№ | Пользователь | Рейтинг |
---|---|---|
1 | tourist | 3985 |
2 | jiangly | 3814 |
3 | jqdai0815 | 3682 |
4 | Benq | 3529 |
5 | orzdevinwang | 3526 |
6 | ksun48 | 3517 |
7 | Radewoosh | 3410 |
8 | hos.lyric | 3399 |
9 | ecnerwala | 3392 |
9 | Um_nik | 3392 |
Страны | Города | Организации | Всё → |
№ | Пользователь | Вклад |
---|---|---|
1 | cry | 169 |
2 | maomao90 | 162 |
2 | Um_nik | 162 |
4 | atcoder_official | 161 |
5 | djm03178 | 158 |
6 | -is-this-fft- | 157 |
7 | adamant | 155 |
8 | awoo | 154 |
8 | Dominater069 | 154 |
10 | luogu_official | 151 |
Is this code below works on all platform with C++11 compiler?
I know that earlier we had to to use "%I64d" for Windows platform and "%lld" for linux like platforms.
long long = (long long)1e18;
printf("%lld\n", a);
Название |
---|
No it doesn't.
UPD: I suddenly realised I might've been wrong. I do have problems with --std=gnu++11 but, apparently, there's no such problem with --std=c++11.
CODE from last round got Accepted. And Codeforces is on windows platform.
you may check it in the Standard but as far as I remember it's now in standard so it should work in every compliant compiler.
Not that this means much when mingw is notoriously non-compliant. Ever tried printing long doubles? (Also, for some reason, you have to read doubles with %lf and print with %f, even though they should be equivalent).
Strangely, it works on every compiler on Codeforces
P.S. WIN32 is defined, as I see
It works. Even
-std=c++11 -Wpedantic
gives no warnings. It seems that the code is correct in ISO C++ 2011 Standard.