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problem link I am doing this question using AVL tree but I am not able to handle the duplicate values in the input. First , I thought of using a vector for each node but that will turn out to be a TLE. Any help would be really appreciated.
Thanks in advance.
use queue in each node to store the ranks
but how will I delete a node ? I mean, if I have a node A (val=10 & rank=1,3,5,10) and its in-order successor node B(val=12 & rank=2,4) . So I have to copy the entire node(val and queue) of node B to node A. Won't it lead to TLE?
yes you are right, i'm sorry.
i did the implementation and it gives TL on test 3. so there must be another way.
seems like
O(nlgn + mlg(n+m))can't fit in the time limit! after some thinking, i approach a way simpler solution, it works as follows:q[x]is a queue that stores all the ranks for valuex, to answer queryI xjust doq[x].push(currentRank)the other queries are the same, you may refer to the code. However it stills TL on the third test. the solution seems to be a way harder.In my opinion O(nlogn) should pass easily. However , only 11 submissions have been there so far for this problem.