I solved TopBiologist by recursion. I want to know if there is any iterative approach? We will need to run loop 6 times to generate sequence of length 6. Is there any shorter way to do this?
# | User | Rating |
---|---|---|
1 | tourist | 3856 |
2 | jiangly | 3747 |
3 | orzdevinwang | 3706 |
4 | jqdai0815 | 3682 |
5 | ksun48 | 3591 |
6 | gamegame | 3477 |
7 | Benq | 3468 |
8 | Radewoosh | 3462 |
9 | ecnerwala | 3451 |
10 | heuristica | 3431 |
# | User | Contrib. |
---|---|---|
1 | cry | 167 |
2 | -is-this-fft- | 162 |
3 | Dominater069 | 160 |
4 | Um_nik | 158 |
5 | atcoder_official | 157 |
6 | Qingyu | 155 |
7 | djm03178 | 151 |
7 | adamant | 151 |
9 | luogu_official | 150 |
10 | awoo | 147 |
I solved TopBiologist by recursion. I want to know if there is any iterative approach? We will need to run loop 6 times to generate sequence of length 6. Is there any shorter way to do this?
Name |
---|
It's similar to converting numbers into the radix 4.
Thanks. Can we write i th element of an integer array like you wrote for string?
You wrote
s += "ACGT"[x % 4]
I wrote this and got compilation error
for(int i=0;i<4;i++) cout<<{1,2,3,4}[i];
I have found an interesting solution without recursion.