born2rule's blog

Invitation To Fool's Programming Contest 2018
By born2rule, history, 6 years ago, In English

After successfully organizing CodeCraft, Felicity 2018 presents Fool's Programming. It's an unusual Coding contest for puzzle lovers hosted on CODECHEF. It is based on concept of April Fool's contest on Codeforces. The problems can not only have unusual solutions, but can also have bizarre problem statements that can make one scratch their brains. Deciphering the questions can at times be more challenging than solving them.

To enjoy competing in this round, along with basic programming skills, you'll need eagle eye to spot the clues and hints hidden in the questions posed to you.

The contest will be hosted on CODECHEF on the Tuesday, 23rd of January, 20:05 PM IST.

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6 years ago, # |
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Auto comment: topic has been updated by born2rule (previous revision, new revision, compare).

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6 years ago, # |
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Just to clarify, I'm the author of April Fools contest series listed in "Similar contests" list and I'm not affiliated with this contest in any way.

Stay tuned for the 6th April Fools contest on Codeforces on April 1st :-)

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    6 years ago, # ^ |
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    This is not a April Fool Contest :'). You did wrong.

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6 years ago, # |
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Auto comment: topic has been updated by born2rule (previous revision, new revision, compare).

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6 years ago, # |
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Contest is going to start in 5 min.

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6 years ago, # |
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Grader has stopped working?

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6 years ago, # |
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502 ,500,504 errors

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    6 years ago, # ^ |
    ← Rev. 2   Vote: I like it +1 Vote: I do not like it

    They will be fixed shortly. Please stay tuned. Edit: Please, try now. It's up.

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6 years ago, # |
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how to solve "Ask Key World" and "Capitals Of the Past"?

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    6 years ago, # ^ |
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    Ask Key World: You need to make a string using the integer array. The characters are encoded in the array given. They are equivalent to ASCII characters of numbers formed. Now, the ith character is dependent on number a[i] — a[i — 1] (assume a[0] = 0). Now, just check if the string exists in the set.

    Capitals of the Past: Just sum the numbers and print the next prime greater than sum. (Hint was reading the last problem (toughest) and seeing "PRIME" written in that [atleast I think so]).

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      6 years ago, # ^ |
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      You are right about the Ask Key World.

      But for Capitals of the Past, complete problem statement was spread across in previous questions. "LEAST PRIME LARGER THAN SUM OF INPUTS". It turned out easier than expected due to sample test cases :P

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6 years ago, # |
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Unofficial Editorial of the contest: https://docs.google.com/document/d/1FDDNaOp3RS6-BCGjfPgYyHsJPazJ5wpkAyp_IDqzNig/edit?usp=sharing

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