214A - System of Equations Of course, we can do this using brute-force method. Does a better way exists please share it. Thanks.
# | User | Rating |
---|---|---|
1 | tourist | 3856 |
2 | jiangly | 3747 |
3 | orzdevinwang | 3706 |
4 | jqdai0815 | 3682 |
5 | ksun48 | 3591 |
6 | gamegame | 3477 |
7 | Benq | 3468 |
8 | Radewoosh | 3462 |
9 | ecnerwala | 3451 |
10 | heuristica | 3431 |
# | User | Contrib. |
---|---|---|
1 | cry | 167 |
2 | -is-this-fft- | 162 |
3 | Dominater069 | 160 |
4 | Um_nik | 158 |
5 | atcoder_official | 157 |
6 | Qingyu | 155 |
7 | djm03178 | 151 |
7 | adamant | 151 |
9 | luogu_official | 150 |
10 | awoo | 147 |
214A - System of Equations Of course, we can do this using brute-force method. Does a better way exists please share it. Thanks.
Name |
---|
$$$a + b ^ 2 = n$$$, so $$$a = n - b ^ 2$$$, so $$$a ^ 2 + b = (n - b ^ 2) ^ 2 + b = b ^ 4 - 2 * n * b ^ 2 + n ^ 2 + b = m$$$.
The last equation can be solved in $$$O(1)$$$. If you don't like math, don't open this link
you won't have much fun, if you try to solve that for $$$b$$$...
I'm sure every heathy person won't solve this problem using Ferrari's formula
Iterate over $$$a$$$ up to $$$\sqrt n$$$. For each $$$a$$$, compute $$$b$$$ from the first equation and check if the second equation holds. The complexity is $$$O(\sqrt n)$$$. If you want something better, have fun with ugly equations.