Given n<=1000000 and k<=n*(n-1)/2 construct a sequence of length n that has exactly k inversions. How do I solve this? Thanks!
# | User | Rating |
---|---|---|
1 | tourist | 3856 |
2 | jiangly | 3747 |
3 | orzdevinwang | 3706 |
4 | jqdai0815 | 3682 |
5 | ksun48 | 3591 |
6 | gamegame | 3477 |
7 | Benq | 3468 |
8 | Radewoosh | 3462 |
9 | ecnerwala | 3451 |
10 | heuristica | 3431 |
# | User | Contrib. |
---|---|---|
1 | cry | 167 |
2 | -is-this-fft- | 162 |
3 | Dominater069 | 160 |
4 | Um_nik | 158 |
5 | atcoder_official | 157 |
6 | Qingyu | 155 |
7 | djm03178 | 151 |
7 | adamant | 151 |
9 | luogu_official | 150 |
10 | awoo | 147 |
Given n<=1000000 and k<=n*(n-1)/2 construct a sequence of length n that has exactly k inversions. How do I solve this? Thanks!
Name |
---|
Every number $$$1 \le i \le n$$$ can add maximum $$$n - i$$$ inversions. So we can run from $$$1$$$ to $$$n$$$ and if $$$cnt_{inversion} + (n - i) \le k$$$ then place $$$i$$$ on maximum right unused position and doing $$$cnt_{inversion} += (n - i)$$$. Else place $$$i$$$ on minimal left unused position and $$$cnt_{inversion}$$$ was not changed.
https://ideone.com/kXZNIe