HOW TO SOLVE THE INEQUALITY i*(i + 1) <= n such that i is maximum possible in O(1) time complexity.is their exist any method.
# | User | Rating |
---|---|---|
1 | tourist | 4009 |
2 | jiangly | 3839 |
3 | Radewoosh | 3646 |
4 | jqdai0815 | 3620 |
4 | Benq | 3620 |
6 | orzdevinwang | 3612 |
7 | Geothermal | 3569 |
8 | ecnerwala | 3494 |
9 | Um_nik | 3396 |
10 | gamegame | 3386 |
# | User | Contrib. |
---|---|---|
1 | Um_nik | 164 |
2 | -is-this-fft- | 162 |
3 | maomao90 | 159 |
3 | atcoder_official | 159 |
5 | cry | 158 |
5 | awoo | 158 |
7 | adamant | 155 |
8 | nor | 154 |
9 | TheScrasse | 153 |
10 | Dominater069 | 152 |
HOW TO SOLVE THE INEQUALITY i*(i + 1) <= n such that i is maximum possible in O(1) time complexity.is their exist any method.
Name |
---|
This is the one I can think of. Solve $$$i^{2}+i-n=0$$$
So just take floor(sol) from the previous equation.
The problem is that solution involves computing square root which is not O(1).
yeah that is the problem, i can find it in sqrt complexity but i guess constant complexity is not possible
Computing the square root of a number is actually very close close to O(1) !
I don't know the complexity exactly but it is described here : https://en.wikipedia.org/wiki/Computational_complexity_of_mathematical_operations