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It's pretty much Knapsack DP.
I will mention the dynamics:
$$$dp_{i,j,0}\ =maximum \ amount \ paid\ for\ first\ i\ elements\ with\ sweetness\ <=j\ and\ operation\ is not\ used.$$$
$$$dp_{i,j,1}\ =maximum \ amount \ paid\ for\ first\ i\ elements\ with\ sweetness\ <=j\ and\ operation\ is\ used.$$$
$$$Transitions\ are\ similar\ to\ Knapsack\ DP.$$$
Your answer will be $$$max(dp[n][m][0]\ ,\ dp[n][m][1])$$$
My solution: https://ideone.com/NgqsT4
Brother please can you clear my doubt I use 3 dp states dp[n][m][flag] The code passed the test cases but when I was using 2 dp states dp[n][m] and was updating the value for flag . Then it was failing on few cases why is so???
This is my previous code:- https://pastebin.com/E1hqm56H
This is new code:- https://pastebin.com/xEqn2Uq8
The problem is with the statement
, since we don't know if flag was true or false, in the returned state,so it may lead to overcount.
Thanks I understood my mistake