why my this code 118446438 get Time limit exceeded and this code 118446206 get accepted in problem 1535C - Нестабильная строка
any hint
# | User | Rating |
---|---|---|
1 | tourist | 4009 |
2 | jiangly | 3831 |
3 | Radewoosh | 3646 |
4 | jqdai0815 | 3620 |
4 | Benq | 3620 |
6 | orzdevinwang | 3529 |
7 | ecnerwala | 3446 |
8 | Um_nik | 3396 |
9 | gamegame | 3386 |
10 | ksun48 | 3373 |
# | User | Contrib. |
---|---|---|
1 | cry | 164 |
1 | maomao90 | 164 |
3 | Um_nik | 163 |
4 | atcoder_official | 160 |
5 | -is-this-fft- | 158 |
6 | awoo | 157 |
7 | adamant | 156 |
8 | TheScrasse | 154 |
8 | nor | 154 |
10 | Dominater069 | 153 |
why my this code 118446438 get Time limit exceeded and this code 118446206 get accepted in problem 1535C - Нестабильная строка
any hint
Name |
---|
for(int i=0 ; i<strlen(s) ; i++)
strlen(s)
has $$$O(n)$$$ complexity so this whole loop has $$$O(n^2)$$$ complexity.strlen() is O(n)
the way strlen works is that it will scan and count, until it finds a null character: every time you call strlen, it scans again and again from the beginning, so it's inefficient, while s.size() is constant