Блог пользователя rafiullah007

Автор rafiullah007, история, 18 месяцев назад, По-английски

include 222483443

using namespace std; ///MD. Rafiullah Al Naim int main(){ long long n; cin >> n;if(n % 2 == 0)cout << n/2 << endl;else cout << -(n+1)/2 << endl;return 0; }486A - Calculating Function

Explaination : Here I have taken a long long x value . Then I have used a logic n%2==0 . Because if we take a value 4 then the mod of 4 will become 0 so we will do n/2 and get the result 2 . Which match our first output. And if it doesn't then we used a logic which is -(n+1)/2 . If we put value 5 over here then we get -3 . Which match our 2nd output .

Thank You . Name : MD.Rafiullah AL NAim (University Of Asia Pacific)

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