Calculating (C(k, k) + C(k+1, k) + C(k+2, k) + ... + C(m, k)) modulo 1234567890 (m >= k) in 1 second? - Codeforces

→ Pay attention

Before contest
Codeforces Round 995 (Div. 3)
01:06:02
Register now »

→ Streams

Codeforces Round 995 Solution Discussion

By aryanc403

Before stream 03:26:02

View all →

→ Top rated

#	User	Rating
1	tourist	3985
2	jiangly	3814
3	jqdai0815	3682
4	Benq	3529
5	orzdevinwang	3526
6	ksun48	3517
7	Radewoosh	3410
8	hos.lyric	3399
9	ecnerwala	3392
9	Um_nik	3392

Countries | Cities | Organizations

→ Top contributors

#	User	Contrib.
1	cry	169
2	maomao90	162
2	Um_nik	162
4	atcoder_official	161
5	djm03178	158
6	-is-this-fft-	157
7	adamant	155
8	awoo	154
8	Dominater069	154
10	luogu_official	150

View all →

→ Find user

→ Recent actions

Detailed →

Calculating (C(k, k) + C(k+1, k) + C(k+2, k) + ... + C(m, k)) modulo 1234567890 (m >= k) in 1 second?

Revision en1, by xuanquang1999, 2016-08-16 15:48:48

Is there a way to do this?

History

Revisions

	Rev.	Lang.	By	When	Δ	Comment
	en2		xuanquang1999	2016-08-16 15:52:00	55	Tiny change: 'to do this?' -> 'to do this if m, k <= 10^9?\n\nPS: C here mean combination number.'
	en1		xuanquang1999	2016-08-16 15:48:48	127	Initial revision (published)