Is it true that if a biconnected component has an odd simple cycle, then ALL edges in that component belong to some (not necessarily the same) odd simple cycle? If that's the case, what would be a formal proof for that? I believe this property would be crucial to solve this problem: http://codeforces.net/problemset/problem/97/E
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Proof that if a biconnected component has an odd simple cycle, then ALL edges in such component belong to some odd simple cycle?
Difference between en1 and en2,
changed 28 character(s)
History
Revisions
| Rev. | Lang. | By | When | Δ | Comment | |
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| en2 |
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pabloskimg | 2018-04-28 09:29:16 | 28 | ||
| en1 |
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pabloskimg | 2018-04-28 08:08:52 | 429 | Initial revision (published) |
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