#include <bits/stdc++.h>
using namespace std;

int main() {
	int t;
	cin >> t;

	for (int test = 1; test <= t; test++) {
		string b;
		cin >> b;

		string a = b.substr(0, 2);

		for (int i = 3; i < b.size(); i += 2) {
			a += b[i];
		}

		cout << a << endl;
	}

	return 0;
}

#include <bits/stdc++.h>

using namespace std;
using ld = long double;
using ll = long long;

void solve() {
    int n;
    cin >> n;
    int a = 0, b = 0;
    for (int i = 0; i < n; i++) {
        int x;
        cin >> x;
        if (x % 2 != i % 2) {
            if (i % 2 == 0) {
                a++;
            } else {
                b++;
            }
        }
    }
    if (a != b) {
        cout << -1 << endl;
    } else {
        cout << a << endl;
    }
}

int main() {
    int n;
    cin >> n;
    while (n--) {
        solve();
    }
}

#include <bits/stdc++.h>
using namespace std;

int main() {
	int t;
	cin >> t;

	for (int test = 1; test <= t; test++) {
		int n, k;
		cin >> n >> k;
		string s;
		cin >> s;

		int res = 0;

		for (int i = 0; i < n;) {
			int j = i + 1;

			for (; j < n && s[j] != '1'; j++);

			int left = s[i] == '1' ? k : 0;
			int right = j < n && s[j] == '1' ? k : 0;
			int len = j - i;

			if (left == k) {
				len--;
			}

			len -= left + right;

			if (len > 0) {
				res += (len + k) / (k + 1);
			}

			i = j;
		}

		cout << res << endl;
	}

	return 0;
}

#include <bits/stdc++.h>

using namespace std;
using ld = long double;
using ll = long long;

void solve() {
    int n;
    cin >> n;
    int cnt = 0;
    for (int i = 2; i * i <= n; i++) {
        while (n % i == 0) {
            cnt++;
            n /= i;
        }
    }
    cnt += n != 1;
    cout << cnt << endl;
}

int main() {
    int n;
    cin >> n;
    while (n--) {
        solve();
    }
}

#include <bits/stdc++.h>
using namespace std;

int main() {
	int test;
	cin >> test;

	while (test--) {
		int n, k;
		cin >> n >> k;
		string s;
		cin >> s;

		vector<int> cnt(26);

		for (char c : s) {
			cnt[c - 'a']++;
		}

		for (int len = n; len >= 1; len--) {
			vector<bool> used(len);
			vector<int> cycles;

			for (int i = 0; i < len; i++) {
				if (used[i]) {
					continue;
				}

				int j = (i + k) % len;
				used[i] = true;
				cycles.push_back(0);
				cycles.back()++;

				while (!used[j]) {
					cycles.back()++;
					used[j] = true;
					j = (j + k) % len;
				}
			}

			vector<int> cur_cnt(cnt);

			sort(cycles.begin(), cycles.end());
			sort(cur_cnt.begin(), cur_cnt.end());

			bool can_fill = true;

			while (!cycles.empty()) {
				if (cur_cnt.back() < cycles.back()) {
					can_fill = false;
					break;
				} else {
					cur_cnt.back() -= cycles.back();
					cycles.pop_back();
					sort(cur_cnt.begin(), cur_cnt.end());
				}
			}

			if (can_fill) {
				cout << len << endl;
				break;
			}
		}
	}
}

#include <bits/stdc++.h>

using namespace std;
using ld = long double;
using ll = long long;

void solve() {
    int n;
    cin >> n;
    vector<int> v(n);
    vector<pair<int, int>> a(n);
    for (int i = 0; i < n; i++) {
        cin >> v[i];
        a[i] = {v[i], i};
    }
    sort(a.begin(), a.end());
    vector<int> p(n);
    int j = 0;
    unordered_multiset<int> next;
    for (int i = 0; i < n; i++) {
        if (i > 0 && a[i].first != a[i - 1].first) {
            j++;
        }
        p[a[i].second] = j;
        next.insert(j);
    }
    unordered_map<int, int> d;
    vector<int> dp1(n), dp2(n), dp3(n), cnt(n);
    for (int i = 0; i < n; i++) {
        if (next.count(p[i])) {
            next.erase(next.find(p[i]));
        }
        if (d.count(p[i] - 1)) {
            if (!d.count(p[i])) {
                dp2[i] = max(dp2[i], dp1[d[p[i] - 1]] + 1);
                if (!next.count(p[i] - 1)) {
                    dp2[i] = max(dp2[i], dp2[d[p[i] - 1]] + 1);
                }
            }
            if (!next.count(p[i] - 1)) {
                dp3[i] = max(dp3[i], dp2[d[p[i] - 1]] + 1);
            }
            dp3[i] = max(dp3[i], dp1[d[p[i] - 1]] + 1);
        }
        if (d.count(p[i])) {
            dp3[i] = max(dp3[i], dp3[d[p[i]]] + 1);
            dp2[i] = max(dp2[i], dp2[d[p[i]]] + 1);
            dp1[i] = dp1[d[p[i]]] + 1;
        } else {
            dp1[i] = 1;
        }
        dp2[i] = max(dp2[i], dp1[i]);
        dp3[i] = max(dp3[i], dp2[i]);
        d[p[i]] = i;
    }
    cout << n - *max_element(dp3.begin(), dp3.end()) << "\n";
}

int main() {
    int n;
    cin >> n;
    while (n--) {
        solve();
    }
}