Whimsical_HITMAN's blog

By Whimsical_HITMAN, history, 13 months ago, In English

https://www.spoj.com/problems/ONEXLIS/

i have been trying to solve the problem for a long time...but couldnt come up with a proper approach... My approach(ig wrong) : when we consider a sequence to be lis, the elements before the last element must have lds(longest strictly decreasing subsequence) > 1; however im unable to implement the idea; any help would be appreciated.

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13 months ago, # |
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Firstly without loss of generality, we can assume that $$$0 \le a_i \le n - 1$$$, by coordinate compression.

Let's try fixing the one pair that is out of order in the subsequence. Define $$$l_x, r_x$$$ to be the longest increasing sequence ending at index $$$x$$$ and the longest increasing sequence starting from index $$$y$$$ respectively. These values can be computed for all $$$x$$$ using a segment tree in one pass. Then the answer to the problem is $$$\max_{i < j, a[i] > a[j]} l_i + r_j$$$. Iterating over $$$j$$$, this is also doable using a segment tree.

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    13 months ago, # ^ |
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    iterating over all j will give tle right?

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      13 months ago, # ^ |
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      For every $$$j$$$ you do $$$O(\log n)$$$ work, so it should not.