jash2703's blog

By jash2703, history, 2 days ago, In English

Can any one solve this

C++ code N^(f(X)) mod M

f(X) is defined as product of primes upto X

1<=N,M<=10^9

1<=X<=10^6

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2 days ago, # |
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For any $$$a, b$$$ and $$$c$$$, $$$(a^b)^c = a^{bc}$$$. So,

int ans = n;
for (int p : primes)
  ans = pow(ans, p, m);

where pow is implemented using fast exponentiation.

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    2 days ago, # ^ |
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    Thank you. Sir