Hi, Codeforces!
I'm delighted to invite you to the best/second best/third best round of 2025 so far! Codeforces Round 997 (Div. 2) will be held on Jan/17/2025 17:35 (Moscow time). You will be presented with at least $$$6$$$ and at most $$$6$$$ problems, one of which might be divided into two subtasks, and $$$2$$$ hours to solve them.
Many of you may not believe it, but the problems were authored and written by nifeshe with a great help from maomao90. Moreover, I would like to thank:
maomao90 for coordinating the round and helping with tasks ideas/preparation.
Alexdat2000 for translating the problems to Russian.
All of our testers: errorgorn, A_G, LipArcanjo, _istil, Markadiusz, Error_Yuan, Intellegent, mwen, LMeyling, hazzlek, iLoveIOI, Rideris, DilshodbekX, chromate00, tibinyte2006 for, believe it or not, testing.
MikeMirzayanov for the Codeforces and Polygon platforms.
Bliznetc for playing chess with me.
And You for participating!
The score distribution is as follows: $$$500-1250-1500-2000-2250-(2750+1250)$$$.
I hope you will find a non-empty subset of problems to be interesting. Good luck!
According to the score distribution, it seems a bit easier than last div2 Round ?!
It's not related .
WOO , I haven't known that yet.I have just supposed this score is equal to difficulty (
no it's not , as cry pointed out in his own blog here
thanks for link;
👍
So now the LGM tag isn't even good enough for the "And You for participating!" line. They've trampled all over the meaning of the word legendary.
Believe it or not, I tested.
As a participant, i will try to solve A within 5 minutes.
i believe in you
Pressure++
Hope we can have easier E and F to solve. E and F for last Div.2 are not fit for rated participant(but it has nothing to do with me thinking they are good problems, especially E is interesting), only two can solve E and no one can solve F is abnormal.
what is the contest duration
Updated the blog
I think this is the new shortest official contest blog, beating the previous contest's blog.
Hoping for the contest to have >2 solves on E, F! (oops)
B seems harder than usual
If I don't become specialist in this contest then I'll
try again in the next one
good luck