((n+m)Cn) %mod here n and m can be upto 10^9 and mod is 10^6+3. Can someone help me in this calculating the correct answer
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((n+m)Cn) %mod here n and m can be upto 10^9 and mod is 10^6+3. Can someone help me in this calculating the correct answer
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You should not ask for the solution of a problem from a running contest. Try yourself or wait for the contest to end.
look at this thread for calculating N!%M in O(MlogN)
and use this fact N! - 1%M = (N!%M)M - 2%M
Why did you do that?
Why are you trying to help him even though the first comment clearly indicates that the question is from a running contest ?
And my point is that he didn't help only him...