Here is the link to the editorial. Feel free to discuss problems and ask me questions. I'll be glad to improve the editorial with your comments.
№ | Пользователь | Рейтинг |
---|---|---|
1 | tourist | 3985 |
2 | jiangly | 3814 |
3 | jqdai0815 | 3682 |
4 | Benq | 3529 |
5 | orzdevinwang | 3526 |
6 | ksun48 | 3517 |
7 | Radewoosh | 3410 |
8 | hos.lyric | 3399 |
9 | ecnerwala | 3392 |
9 | Um_nik | 3392 |
Страны | Города | Организации | Всё → |
№ | Пользователь | Вклад |
---|---|---|
1 | cry | 169 |
2 | maomao90 | 162 |
2 | Um_nik | 162 |
4 | atcoder_official | 161 |
5 | djm03178 | 158 |
6 | -is-this-fft- | 157 |
7 | adamant | 155 |
8 | awoo | 154 |
8 | Dominater069 | 154 |
10 | luogu_official | 150 |
Название |
---|
I'm not getting div2 c ...how it is linked to knapsack?? can you explain the logic more clearly??
We want to find the probability of gaining i scores in games other than G. It's similar to finding in how many ways we gain i scores. It's a knapsack problem.
we need to gain i scores in such a way that after adding G to it .It must become greater than n*(n+1)/4.In other words we need to look for only those i's such that after adding G to it ,it can become greater than n*(n+1)/4.Am i right?
and we'll use knapsack to find those i's and we won't be using G as a weight?
Correct.
Thank you :)