Perhaps this is an unpopular opinion but I think we need more testers that are on the lower side of the rating spectrum. Having only red/orange testers for Div 2 contests might (and does) result in underestimation of the difficulty of the proposed problems. Blue/cyan or even green/gray form a more representative sample for the actual contestants. I understand that there should be a few highly rated and experienced testers but having only them can result in speedforces rounds for Div 2 participants.
→ Pay attention
Before contest
CodeTON Round 9 (Div. 1 + Div. 2, Rated, Prizes!)
42:56:01
Register now »
CodeTON Round 9 (Div. 1 + Div. 2, Rated, Prizes!)
42:56:01
Register now »
*has extra registration
→ Top rated
| # | User | Rating |
|---|---|---|
| 1 | tourist | 4009 |
| 2 | jiangly | 3823 |
| 3 | Benq | 3738 |
| 4 | Radewoosh | 3633 |
| 5 | jqdai0815 | 3620 |
| 6 | orzdevinwang | 3529 |
| 7 | ecnerwala | 3446 |
| 8 | Um_nik | 3396 |
| 9 | ksun48 | 3390 |
| 10 | gamegame | 3386 |
→ Top contributors
| # | User | Contrib. |
|---|---|---|
| 1 | cry | 167 |
| 2 | Um_nik | 163 |
| 3 | maomao90 | 162 |
| 3 | atcoder_official | 162 |
| 5 | adamant | 159 |
| 6 | -is-this-fft- | 158 |
| 7 | awoo | 157 |
| 8 | TheScrasse | 154 |
| 9 | Dominater069 | 153 |
| 9 | nor | 153 |
→ Find user
→ Recent actions
Round 1B of the Google CodeJam contest just finished. What are your thoughts/comments on this round? I found the problems to be a bit unbalanced in difficulty which resulted in a lot of ties.
The PEG Wiki (http://wcipeg.com/wiki) is down for quite some time now although the main site (https://wcipeg.com/main) seems to be working fine. Does anybody know what happened to it? Is this something permanent? The wiki had some excellent articles which shouldn't be lost.
So I came up with this problem yesterday, which I couldn't solve. With a quick google search I found nothing relevant so I thought I could ask here for help.
The Problem
You are given a tree T with n nodes and an integer k. You are asked to find the length of longest path in T which has exactly k inversions. Here we define path inversions for a specific path P as the number of inversions in the array of the nodes visited in P, in that order. If there is no such path output - 1.
Let's consider the above tree for example, with k = 2. The answer is 4 since the path 1 - 6 - 2 - 5 has exactly 2 inversions. Note that the path 5 - 2 - 4 also has 2 inversion however it isn't the path with the maximum length.
I am looking for solutions with complexity better than O(n2·logn)
Thank you for your time.
Codeforces (c) Copyright 2010-2024 Mike Mirzayanov
The only programming contests Web 2.0 platform
Server time: Nov/21/2024 22:38:59 (j2).
Desktop version, switch to mobile version.
Supported by
